http://physics.bu.edu/~duffy/semester1/c4_maxheight.html WebDec 21, 2024 · How do I calculate the maximum height of a projectile with θ = 40° and v₀=5 m/s? To calculate it: Start from the equation for the vertical motion of the projectile: y = vᵧ × t - g × t² / 2, where vᵧ is the …
Launching and landing on different elevations - Khan Academy
WebThe time for this effect to take place is the length of time of the flight of the projectile. The distance the projectile travels is determined by the horizontal component of its flight. If you multiply the horizontal speed by time in the air you get the distance traveled. Web(c) Determine her initial speed V0 at the launch point in terms of g and h. (d) Determine her maximum airborne height ymax in terms of h, g, and the horizontal speed at that height, v0x. (e) Use the x-component of the answer to part (c) to eliminate from the answer to part (d), giving the height ymax in terms of g, h, and the launch angle . cancer astrology necklace
Maximum Height, Time of Flight and Range of a Projectile
WebJan 24, 2014 · http://www.physicshelp.caGO AHEAD and click on this site...it wont hurt.Free simple easy to follow videos all organized on our website WebDec 21, 2024 · Start from the equation for the vertical motion of the projectile: y = vᵧ × t - g × t² / 2, where vᵧ is the initial vertical speed equal to vᵧ = v₀ × sin (θ) = 5 × sin (40°) = 3.21 … WebWhat we could ultimately answer is the magnitude of the horizontal displacement (i.e. the distance from the cannon to the place where the projectile lands). The length of the 'well' will remain forever a mystery! ( 27 votes) Show more... Meena Ahmed 11 years ago @ 15:12 , why didn't Sal use the formula: s = Vi (x) + a (deltaT) fishing supply stores laughlin az