Web30 mrt. 2024 · Misc 20 If a, b, c are in A.P, ; b, c, d are in G.P and 1/c, 1/d, 1/e are in A.P. prove that a, c, e are in G.P. It is given that a, b, c are in AP So, their common difference is same b a = c b b + b = c + a 2b = c + a b = ( + )/2 Also given that b, c, d are in GP So, their common ratio is same / = / c2 = bd Also 1/c, 1/d, 1/e are in A.P. WebClearly, (a 3 +b 3)-1, (b 3 +c 3)-1, (c 3 +d 3)-1 are in G.P. with commom ratio 1/r 3. Related Questions If a n be the n th term of an AP and if a 7 = 15 then t
Given a^x = b^y = c^z = d^u and a,b,c,d are in G.P., then x,y
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If a, b and c are in GP, then `(b-a)/(b-c)+(b+a)/(b+c)`= - YouTube
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